店铺对应的推广用户

master
wangweijia 6 years ago
parent a49679b53a
commit fef8a6859f

@ -33,14 +33,16 @@
order by t1.create_time desc,t2.id desc,t1.user_id desc order by t1.create_time desc,t2.id desc,t1.user_id desc
</select> </select>
<select id="selectCustomerInfoBySellerId" resultType="com.kiisoo.ic.customer.bean.OpCustomerDTO"> <select id="selectCustomerInfoBySellerId" resultType="com.kiisoo.ic.customer.bean.OpCustomerDTO">
select SELECT t2.id,t2.`name`,
t2.id,t2.`name`,t2.member_id as idCard,GROUP_CONCAT(DISTINCT t0.`name`) as shopName, GROUP_CONCAT(DISTINCT t4.`name`) as sellerName, t3.birthday, t2.phone t2.member_id as idCard,t0.name as shopName,t0.code as shopCode,
,t3.name as vipName,t3.phone as vipPhone, t1.create_time t4.name as sellerName, t3.birthday, t2.phone,
from t3.name as vipName,t3.phone as vipPhone, t5.staff_code as sellerCode, t1.create_time as createTime
poi_store t0, from op_seller_customer_relation t1
op_seller_customer_relation t1 LEFT JOIN privilage_user t4 on t1.user_id = t4.id, left join poi_store t0 on t0.id = t1.store_id
op_customer t2 LEFT JOIN op_vip t3 on t2.member_id = t3.id left join poi_store_staff t5 ON t5.store_id = t0.id and t1.user_id = t5.id
where t0.id = t1.store_id and t1.customer_id = t2.id LEFT JOIN op_customer t2 ON t2.id = t1.customer_id
LEFT JOIN op_vip t3 ON t3.id = t2.member_id
LEFT JOIN privilage_user t4 ON t4.id = t5.user_id where 1 =1
and t1.user_id = #{sellerId} and t1.user_id = #{sellerId}
<if test="startDate != null"> <if test="startDate != null">
and t1.create_time >= #{startDate} and t1.create_time >= #{startDate}

Loading…
Cancel
Save